Didn't you ask this yesterday? As BobPursley answered then, you need to know the velocity at the bottom of the loop. You still have not provided that information.
You can make a calculation of that velocity by using conservation of energy IF the velocity is zero at the top of the loop. They may expect you to make that assumption.
V(@ bottom)= sqrt(2gH) = 2 sqrt(gR)
Wap (@bottom)
= M (V^2/R + g)
= 5 M g
It is somewhat surprising that it is independent of R.
I have seen rides like that at carnival amusement parks, but never went on one.
Suppose the vertical loop has a radius of 8.92 m. What is the apparent weight (Wap) of a rider on the roller coaster at the bottom of the loop? (Assume that friction between roller coaster and rails can be neglected. Give your answer in terms of m and g.)
3 answers
so Wap will equal in terms of m and g this.
m ( (sqrt ( r*g )/ r ) + g )
m ( (sqrt ( r*g )/ r ) + g )
v^2 = 4 g r
so
v^2/r = 4 g
so weight = m(4g+g) = 5 m g
so
v^2/r = 4 g
so weight = m(4g+g) = 5 m g