vf^2=vi^2+2ad
0=6^2+2*(-2)d
solve for distance d.
how long?
avg speed * time= distance
3 m/s * time=d
time= d/3
Suppose the sprinter continues to run at 6m/s until the end pf the race. After crossing the finish line the sprinter decelerates at 2m/s^2.a) how long it takes her to stop b) how far does the sprinter travel while stopping?
4 answers
Reason for 3 m/s
average speed = (6+0)/2
which is 3