revenue is price * quantity
r = x*p = x√(75-2x)
I hope this is for a calculus class, because we can now use r' to find the max:
r' = 3(25-x)/√(75-2x)
r'=0 when x = 25
Suppose the quantity demanded per week of a certain dress is related to price by the demand equation p=√75-2x. In order to maximize revenue, how many dresses should be made and sold each week?
1 answer