To find the probability of students with masses more than 72 kg, we need to find the z-score for 72 kg and then use the standard normal distribution table to find the probability.
First, calculate the z-score:
z = (X - μ) / σ
z = (72 - 68) / 9
z = 0.44
Next, find the probability using the standard normal distribution table:
P(z > 0.44) = 1 - P(z < 0.44)
Looking up the z-score of 0.44 in the standard normal distribution table, we find that P(z < 0.44) ≈ 0.6700
Therefore, the probability of students with masses more than 72 kg is:
P(z > 0.44) = 1 - 0.6700 = 0.3300 or 33%
Suppose the mass of students, in kg is N(68; 9) distributed. Find the probability of students with the masses more than 72 kg.
0.9082
0.0918
0.6700
0.33
1 answer
1 answer