Suppose the integral from 2 to 8 of g of x, dx equals 13, and the integral from 6 to 8 of g of x, dx equals negative 3, find the value of 2 plus the integral from 2 to 6 of g of x, dx.

16
18
8
32

2 answers

note that

∫[2,6] + ∫[6,8] = ∫[2,8]
32