Suppose the average body temp is 98.6 assume the variable is normally distributed with a standard deviation of .74 degrees. suppose a sample of 100 is taken. what is the probability that the mean is below 98.4??? Between 98.5 AND 98.7??

Question

Suppose the average body temp is 98.6  assume the variable is normally distributed with a standard deviation of .74 degrees.  suppose a sample of 100 is taken.  what is the probability that the mean is below 98.4??? Between  98.5 AND 98.7??

Kuai · Answer

z = (98.5-98.6)/.74/sqr(100) z = (98.7- 98.6)/.74/sqr(100)