Look up the heat of fusion of ethanol.
Heat in water freezing= masswater*Hfwater
Heat in alchol freezing=massalcohol*Hfalc
set the equal, and solve for mass of alcohol.
Suppose the amount of heat removed when 3.0kg of water freezes at 0 degree C were removed from ethyl alcohol and its freezing/melting point of -114 degree C. How many kilograms of ethyl alcohol would freeze?
PLEASE GIVE ME SOME HINTS!!!THANKS A LOT!!!!
4 answers
Am i Correct The correct answer is 9.3 kg ?
(m_(water ) 〖Lf〗_water)/〖Lf〗_alcohol =m_alcohol
(3.0×(33.5×〖10〗^4 ))/((10.8×〖10〗^4 ) )=m_alcohol=9.3kg
Maryo you are right! :)
(3.0×(33.5×〖10〗^4 ))/((10.8×〖10〗^4 ) )=m_alcohol=9.3kg
Maryo you are right! :)
i guess the correct answer is 9.3 kg. but i don't know how to get this answer?
3 answers