Asked by Student in Need
Suppose that you and I are having a singing contest, and you produce a sound intensity (measured in W/ m2) about 32 times greater than mine. How many dB louder than me are you singing ?
His is 30dB.
For 79 times greater the answer is 19dB
For 63 times greater the answer is 18dB
How do I calculate for 32 times greater
His is 30dB.
For 79 times greater the answer is 19dB
For 63 times greater the answer is 18dB
How do I calculate for 32 times greater
Answers
Answered by
drwls
Let the two intensities be I1 and I2.
10 log(10)I2 - 10log(10)I1
= dB difference
= 10 log(10)[I2/I1]
= 10log(10)32 = 15.1 dB
It doesn't matter what sound intensity power units are used. It is the intensity ratio that matters.
10 log(10)I2 - 10log(10)I1
= dB difference
= 10 log(10)[I2/I1]
= 10log(10)32 = 15.1 dB
It doesn't matter what sound intensity power units are used. It is the intensity ratio that matters.
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