d[x^2y + y^2x] = 0 -->
2xydx + x^2dy + 2xydy + y^2dx = 0 ---->
(2xy + y^2)dx + (2xy + x^2) dy = 0 ---->
dy/dx = -(2xy + y^2)/(2xy + x^2)
Suppose that x and y are related by the given equation and use implicit differentiation to determine dy/dx.
x^2y + y^2x = 3
2 answers
use the product rule for each term on the left side
x^2(dy/dx) + y(2x)(dx/dx) + y^2(dx/dx) + x(2y)(dy/dx) = 0
x^2(dy/dx) + 2xy + y^2 + 2xy(dy/dx) = 0
dy/dx is a common factor, so ...
dy/dx(x^2 + 2xy) = -2xy - y^2
dy/dx = (-2xy - y^2)/(x^2 + 2xy)
x^2(dy/dx) + y(2x)(dx/dx) + y^2(dx/dx) + x(2y)(dy/dx) = 0
x^2(dy/dx) + 2xy + y^2 + 2xy(dy/dx) = 0
dy/dx is a common factor, so ...
dy/dx(x^2 + 2xy) = -2xy - y^2
dy/dx = (-2xy - y^2)/(x^2 + 2xy)
1 answer