number of advance --- x
number of same day --- y
x+y = 55
y = 55-x
40x + 20y = 1800
40x + 20(55-x) = 1800
continue
strange price for tickets, usually at the door they are more expensive
Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost
$40
and same-day tickets cost
$20
. For one performance, there were
55
tickets sold in all, and the total amount paid for them was
$1800
. How many tickets of each type were sold?
1 answer
1 answer