To solve this problem, let’s analyze the information given.
Initial Data:
- Water level is 22 feet before the rain starts (at day 0).
- Water level is 34 feet after 3 days of rain.
- Water level is 62 feet after 10 days of rain.
Now, let’s perform the tasks step by step.
a. Find the rate of change (slope).
Using the two data points:
- After 3 days: (3, 34)
- After 10 days: (10, 62)
The formula for slope (rate of change) is given by: \[ \text{slope} (m) = \frac{y_2 - y_1}{x_2 - x_1} \] Where \((x_1, y_1) = (3, 34)\) and \((x_2, y_2) = (10, 62)\).
So: \[ m = \frac{62 - 34}{10 - 3} = \frac{28}{7} = 4 \]
b. Find the y-intercept.
The y-intercept is the water level when \(x = 0\) (before the rain starts). From the problem statement, we know the water level before rain began was: \[ \text{y-intercept} = 22 \]
c. Write an equation in slope-intercept form (y = mx + b).
Using the slope \(m = 4\) and the y-intercept \(b = 22\): \[ y = 4x + 22 \]
d. Write the equation in standard form.
Standard form is typically expressed as \(Ax + By = C\). Starting with the slope-intercept form: \[ y = 4x + 22 \] We can rearrange this: \[ -4x + y = 22 \]
To commonly express this in standard form: \[ 4x - y = -22 \] However, standard form traditionally keeps \(A\) as a non-negative integer, so we can multiply through by -1: \[ -4x + y = 22 \]
Final Responses:
- a: 4 (rate of change)
- b: 22 (y-intercept)
- c: \(y = 4x + 22\) (slope-intercept form)
- d: \(-4x + y = 22\) (standard form)