To determine the slope, y-intercept, and write the equations for this scenario, let's first summarize the information given:
- The initial water level before the rain began is 22 feet.
- After 3 days of rain, the water level is 34 feet.
- After 10 days of rain, the water level is 62 feet.
a. What is the rate of change (slope) for this scenario?
We can find the slope (\(m\)) using the formula:
\[ m = \frac{\Delta y}{\Delta x} = \frac{y_2 - y_1}{x_2 - x_1} \]
where \((x_1, y_1) = (3, 34)\) and \((x_2, y_2) = (10, 62)\).
Calculating the slope:
\[ m = \frac{62 - 34}{10 - 3} = \frac{28}{7} = 4 \]
Response area: 4 (the rate of change is 4 feet per day)
b. What is the y-intercept for this scenario?
The y-intercept is the value of \(y\) when \(x = 0\). From the problem statement, we know that before the rain began, the water level was 22 feet.
Response area: 22 (the y-intercept is 22 feet)
c. Write an equation for the scenario in slope-intercept form.
The slope-intercept form of a linear equation is given by:
\[ y = mx + b \]
Substituting the slope (\(m = 4\)) and y-intercept (\(b = 22\)) into the equation:
\[ y = 4x + 22 \]
Response area: \(y = 4x + 22\)
d. Write this equation in standard form.
The standard form of a linear equation is given by:
\[ Ax + By = C \]
Starting from the slope-intercept form \(y = 4x + 22\), we can rearrange it into standard form:
- Subtract \(4x\) from both sides: \[ -4x + y = 22 \]
- To get \(A\) positive, we can multiply the entire equation by -1: \[ 4x - y = -22 \]
Response area: \(4x - y = -22\)
To summarize:
- a: 4
- b: 22
- c: \(y = 4x + 22\)
- d: \(4x - y = -22\)