Suppose that the perimeter of a rectangle is 48 ft and the length is thrice the width. What are the idmensions of this rectangle and what is the area?

Answer 1

P = Perimeter

L = Length

W = Width

P = 2 W + 2 L = 2 ( W + L )

L = 2 W

P = 2 ( W + L ) = 2 ( W + 2 W ) = 2 * 3 W = 6 W

48 = 6 W Divide both sides by 6

48 / 6 = 6 W / 6

8 = W

W = 8 ft

L = 2 W = 2 * 8 = 16 ft

P = 2 ( W + L ) = 2 ( 8 + 16 ) = 2 * 24 = 48 ft

Answer 2

A = W * L = 8 * 16 = 128 ft ^ 2