translating your conditions:
W = k * w* h^2 / l
given: w = 3in, h = 4in, l = 6 ft or 72 in , W = 28 tons
28 = k(3)(16)/72
k = 42
W = 42 * w* h^2 / l
plugging in the second case:
W = 42(5)(16)/240 = 14 tons
Suppose that the maximum weight that a certain type of rectangular beam can support varies inversely as its length and jointly as its width and the square of its height. Suppose also that a beam
3
inches wide,
4
inches high, and
6
feet long can support a maximum of
28
tons. What is the maximum weight that could be supported by a beam that is
5
inches wide,
4
inches high, and
20
feet long?
1 answer
2 answers