Suppose that the gravitational acceleration on a certain planet is only 3.1 m/s2. A space explorer standing on this planet throws a ball straight upward with an initial velocity of 25 m/s.
(a) What is the velocity of the ball 4 seconds after it is thrown?
m/s
(b) How much time elapses before the ball reaches the high point in its flight?
s
3 answers
a.37.4m/s b.5 s
How do you figure it out?
A.) v=vo+at
vo=25m/s. a=3.1 m/s^2 t=4s
v=(25m/s)+(3.1m/s^2)(4s)
v=(25m/s)+(12.4m/s)
v=25m/s+12.4m/s
v=37.4 m/s
vo=25m/s. a=3.1 m/s^2 t=4s
v=(25m/s)+(3.1m/s^2)(4s)
v=(25m/s)+(12.4m/s)
v=25m/s+12.4m/s
v=37.4 m/s
2 answers