Suppose that the endpoints of one leg of a 45°-45°-90° triangle are (0, 3) and (4, –1). What is the length of the hypotenuse?

Answer 1

The distance between the two points is √(16+16) = √32

So, the hypotenuse is √32*√2 = √64 = 8

Answer 2

Find the distance EA for the points E(2, 3) and A(4, 2).