55% are below x
z = .1 ---> F(z) about .55
.1 = (x - 75.5)/10.3
x - 75.5 = 1.03
x = 76.5
Suppose that the average weight of students in a statistics class is 75.5 kilograms with a standard deviation of 10.3 kilograms.
A. 45% of the student weights are above ____ kilograms?
Z=.3264=x-75.5/10.3 Now what?
3 answers
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