Z = (score-mean)/SD = (180-170)/5 = 2
a. Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability between score and mean for Z score. Multiply by 50 ≠ 29
b. Z = (176-170)/5 = 6/5 = 1.2
Smaller portion multiplied by 50 ≠ 7
Suppose that people's heights (in centimeters) are normally distributed, with a mean of 170 and a standard deviation of 5. We find the heights of 50 people. (You may need to use the standard normal distribution table. Round your answers to the nearest whole number.)
(a) How many would you expect to be between 170 and 180 cm tall? =29
b How many would be taller than 176 cm=7
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