Suppose that in one week at a certain casino there are 25,000 independent plays at roulette. On each play, the gamblers stake $1 on red. Is the chance that the casino will win more than $1000 from these 25,000 plays closest to 2% 50% or 98% explain.

Answer 1

The probability of getting red on a single roulette play is 9/19 = 47.37%.

The expected house winning per spin, with $1 bets, is .5263-.4737 = $0.052

After 25,000 spins, the house wins about $1315, on the average. There is a better tnan 50% chance the house will win $1000. 98% and 2% are too far off.