Suppose that b is proportional to c, and inversely

proportional to the square of d. If b = 45 when
c = 40 and d = 2, find b when c =20 and d = 3.

2 answers

we have b = kc/d^2
So, bd^2/c = k is constant

That mean you want b such that

9b/20 = 45*2^2/40
...
I'm not that good at math Steve. Would you describe for me in a simpler way?
Thank you,
Kim