It sounds like a cubic container
s = 6x^2
ds/dx = 12x
so, when x=9, ...
v = a(a+1)(a+4)
dv/dt = (3a^2 + 10a + 4) da/dt
Suppose that a square container is to be filled with water.
a.What is the rate at which the surface area of the container(S) changes with respect to the length of the edge(x) when the edge is equal to 9 inches?
b. The dimensions of the container are :a,a + 1,a + 4. how fast is the volume V increasing a increases?
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