Suppose that a kid was casually sledding down a gentle slopping hill going 6 feet per second. Then, he hit a steeper part of the hill and started accelerating at a rate of 1.2 feet/second squared. At the bottom of the steep part of the hill he was going 10.56 feet/second. How long was the steep part of the this hill?
2 answers
"10th grade" is not the subject
The change in speed is 9.26 ft/s.
Time spent accelerating = 9.26/1.2 = 7.72 seconds
The average speed on the steep part was 5.88 ft/s
Distance = 7.72 s * 5.88 ft/s= 45.4 feet
Time spent accelerating = 9.26/1.2 = 7.72 seconds
The average speed on the steep part was 5.88 ft/s
Distance = 7.72 s * 5.88 ft/s= 45.4 feet
1 answer