To find the amount of money in the account after 9 years with annual compounding interest, we can use the formula for compound interest:
\[ A = P(1 + r)^t \]
Where:
- \( A \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount (the initial amount of money).
- \( r \) is the annual interest rate (decimal).
- \( t \) is the number of years the money is invested or borrowed.
Given:
- \( P = 90,000 \)
- \( r = 5% = 0.05 \)
- \( t = 9 \)
Plugging in the values:
\[ A = 90,000(1 + 0.05)^9 \]
Calculating \( (1 + 0.05)^9 \):
\[ A = 90,000(1.05)^9 \]
Now calculate \( (1.05)^9 \):
\[ (1.05)^9 \approx 1.551328 \]
Now, substituting this back into the equation for \( A \):
\[ A \approx 90,000 \times 1.551328 \approx 139,619.52 \]
Thus, the amount of money in the account after 9 years is approximately $139,619.52.