Suppose that 1.78 x 10^3 kg of Fe are obtained from a 5.80 x 10^3 kg sample of Fe2O3. Assuming that the reaction goes to completion, what is the percent purity of Fe2O3 in the original sample?

Answer 1

Convert kg Fe2O3 to kg Fe. The easy way to do that is
5.80E3 kg x (2*molar mass Fe/molar mass Fe2O3) = ?
Then %purity = (1.78E3/?)*100 = ?