A is in QII, so cosA = -5/13
B is in QIV, so cosB = 24/25
Now, you have
cos(A-B) = cosAcosB + sinAsinB
...
Suppose sinA = 12/13 with 90º≤A≤180º. Suppose also that sinB = -7/25 with -90º≤B≤0º. Find cos(A - B).
2 answers
What kinda answer is that Steve
EH?
EH?
0 answers