Suppose r =

4t
3−27
3
and
s = t
2 + 3t, determine ds
dr

1 answer

To find the derivative of s with respect to r, we use the chain rule:

ds/dr = ds/dt * dt/dr

First, let's find ds/dt:

ds/dt = d/dt (t^2 + 3t) = 2t + 3

Now, let's find dt/dr:

r = 4t^3 - 27
dr/dt = 12t^2
dt/dr = 1 / (dr/dt)
dt/dr = 1 / (12t^2)

Putting it all together:

ds/dr = (2t + 3) * (1 / (12t^2))
ds/dr = (1 / 6t^2) + (1 / 4t)

Therefore, the derivative of s with respect to r is ds/dr = (1 / 6t^2) + (1 / 4t).