Asked by HM
Suppose one card is selected at random from an ordinary deck of 52 playing cards.
Let
A= event a diamond is selected
B=event a club is selected
Determine P(A|(not B))
DrBob said it is 1/3
but how did he get it?
I keep getting answer
1 or 21/26
Let
A= event a diamond is selected
B=event a club is selected
Determine P(A|(not B))
DrBob said it is 1/3
but how did he get it?
I keep getting answer
1 or 21/26
Answers
Answered by
Damon
If you eliminate the 1/4 of the cards that are clubs, one third of what is left are diamonds.
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