if NOt B, then the card has to be a diamond, heart, or spade.
Pr(A|NOT B)=1/3
Suppose one card is selected at random from an ordinary deck of 52 playing cards.
Let
A= event a diamond is selected
B=event a club is selected
Determine P(A|(not B))
Could some one explain this to me and tell me how they got the answer
1 answer