(x-1)/(x^4-1) = 1/((x+1)(x^2+1)) for x≠1
There is a hole at x=1
|x-3|/(x-3) = 1 if x>3
= -1 if x<3
So there is a hole at x=3
lim(x→2-) f(x) = 1/15
lim(x→2+) f(x) = -1
So there is a jump discontinuity at x=2
suppose f(x) = {x-1/x^4-1 if x <= 2 and |x-3|/x-3 if 2<x
Identify any points of discontinuity, and determine (giving reasons) if they are removable, infinite (essential), or jump discontinuities.
1 answer
1 answer