Suppose F(x)=f(x)g(2x) . If f(1)=3 , f′(1)=3 , g(2)=2 , and g′(2)=7 , find F′(1).

F′(1)=

2 answers

′ is supposed to be the prime(')
F''(x) = f'(x)g(2x) + f(x)g'(2x)

==> F''(1) = (3)(2) + (3)(7) = answer