Suppose f(x) = 4x^5-(1/x^4)
Find the slope of the tangent line to the graph of y = f^–1(x) at (3, 1).
You get:
1/24
1/16
00062
1620
972
2 answers
Got this one. Its 1/24 correct?
Its 1/24, the slope of the tangent line to the graph y=f^-1(x) at (3,1) is the reciprocal of the slope of the tangent line to the graph y=f(x) at (1,3).
So f'(x)=20x^4+4/x^5 so f'(1)=20+4=24
So the slope of the tangent is 1/24
So f'(x)=20x^4+4/x^5 so f'(1)=20+4=24
So the slope of the tangent is 1/24
3 answers