f(2.01) = √9.03
f(2) = √9
avg rate of change = (√9.03 - √9)/(2.01-2)
= ....
I get .49958..
Suppose
f(t)=sqrt(3t+3)
What is the average rate of change of f(t) with respect to t as t changes from 2 to 2.01?
The AROC is:_____
3 answers
Yes that is correct. This is what i got also after working it 10 times haha.
why did you doubt it ?