Suppose f(pi/6) = 7 and f’(pi/6) = 2

Question

and let g(x) = f(x)cosx and h(x) = sinx/f(x)
g’(pi/6)=
h’(pi/6)=

Answer 1

g' = f' cosx - f sinx
h' = (f' sinx - f cosx)/f^2
so plug in your numbers. Post your work if you get stuck