To find the value of the investment after 2 decades, we can plug in x = 2 into the function f(x) = 2300 * 2^x.
f(2) = 2300 * 2^2
= 2300 * 4
= 9200
Therefore, the investment is worth $9,200 after 2 decades. Answer: $9,200.
Suppose an investment of $2,300 doubles in value every decade. The function f left parenthesis x right parenthesis equals 2300 times 2 superscript x baseline gives the value of the investment after x decades. How much is the investment worth after 2 decades?
(1 point)
Responses
$2,355,200
$2,355,200
$92,000
$92,000
$46,000
$46,000
$9,200
1 answer
1 answer