Suppose an average person blinks 15 times per hour. How many times does an average person blink in a year? Write the answer in scientific notation (Hint: 1 year = 365 days, 1 day = 24 hours).(1 point) Respones

Question

1.314 × 10^5
1.314 × 10^4
1.314 × 10^-4
1.314 × 10^-5

Answer 1

To find out how many times an average person blinks in a year, we first need to determine the total number of hours in a year.

1. Calculate the total number of hours in a year:

\[ 365 , \text{days/year} \times 24 , \text{hours/day} = 8760 , \text{hours/year} \]

2. Calculate the total number of blinks in a year:

\[ 15 , \text{blinks/hour} \times 8760 , \text{hours/year} = 131400 , \text{blinks/year} \]

3. Convert the result to scientific notation:

\[ 131400 = 1.314 \times 10^5 \]

Thus, the average person blinks \(1.314 \times 10^5\) times in a year.

The correct response is:

1.314 × 10^5

Answer 2

What is the number 7.3 x 10^-8 written in decimal notation

Answer 3

To convert the number \( 7.3 \times 10^{-8} \) to decimal notation, you move the decimal point to the left by 8 places (since the exponent is -8).

Starting with \( 7.3 \):

• Move the decimal point 1 place to the left: \( 0.73 \)
• Move the decimal point 2 places to the left: \( 0.073 \)
• Move the decimal point 3 places to the left: \( 0.0073 \)
• Move the decimal point 4 places to the left: \( 0.00073 \)
• Move the decimal point 5 places to the left: \( 0.000073 \)
• Move the decimal point 6 places to the left: \( 0.0000073 \)
• Move the decimal point 7 places to the left: \( 0.00000073 \)
• Move the decimal point 8 places to the left: \( 0.000000073 \)

Thus, \( 7.3 \times 10^{-8} \) in decimal notation is:

0.000000073