Suppose a spider was able to create one thread that would extend from the top-right back corner of its tank to the bottom-left front corner. Approximately how long would that thread need to be for the tank below? The path of the spider's thread is shown with a red dotted line. Round your answer to the nearest tenth of an inch. Show your work. The length of the prism is 35 cm, the width is 12 cm, the height is 16 cm. The diagonal of the bottom of the tank is__________inches. To the nearest tenth of an inch, the length of the spider's thread is__________inches.

1 answer

To find the length of the spider's thread, we will use the three-dimensional distance formula, which can be visualized as the diagonal of a rectangular prism. The formula for the diagonal \(d\) of a rectangular prism with dimensions length \(l\), width \(w\), and height \(h\) is given by:

\[ d = \sqrt{l^2 + w^2 + h^2} \]

Given the tank dimensions:

  • Length \(l = 35 , \text{cm}\)
  • Width \(w = 12 , \text{cm}\)
  • Height \(h = 16 , \text{cm}\)

We can plug in these values into the formula.

  1. Calculate \(l^2, w^2,\) and \(h^2\):

    • \(l^2 = 35^2 = 1225\)
    • \(w^2 = 12^2 = 144\)
    • \(h^2 = 16^2 = 256\)
  2. Sum these values: \[ l^2 + w^2 + h^2 = 1225 + 144 + 256 = 1625 \]

  3. Now take the square root: \[ d = \sqrt{1625} \] Calculating the square root: \[ \sqrt{1625} \approx 40.311 \]

Next, we need to convert centimeters to inches, knowing that \(1 , \text{inch} = 2.54 , \text{cm}\): \[ d , \text{in inches} = \frac{40.311 , \text{cm}}{2.54} \approx 15.87 , \text{inches} \]

Rounding to the nearest tenth, we find:

  • The length of the diagonal of the bottom of the tank is approximately 15.9 inches.
  • The length of the spider's thread is approximately 15.9 inches.

Final answers:

  • The diagonal of the bottom of the tank is 15.9 inches.
  • The length of the spider's thread is 15.9 inches.