To find the length of the spider's thread, we need to find the length of the diagonal of the tank. We can use the Pythagorean theorem to calculate this.
Let's call the length of the tank l, the width w, and the height h.
Using the Pythagorean theorem, we have:
l^2 = w^2 + h^2
Since the diagonal of the bottom of the tank is given as 9 inches, l = 9 inches.
Substituting this value into the equation, we have:
9^2 = w^2 + h^2
81 = w^2 + h^2
To find the length of the spider's thread, we need to find the hypotenuse of the right triangle formed by the tank's width (w) and height (h).
Using the Pythagorean theorem again, we have:
Thread length^2 = w^2 + h^2
Thread length = sqrt(w^2 + h^2)
Thread length = sqrt(81)
Thread length ≈ 9.0 inches
Rounded to the nearest tenth of an inch, the length of the spider's thread is 9.0 inches.
Suppose a spider was able to create one thread that would extend from the top-right back corner of its tank to the bottom-left front corner. Approximately how long would that thread need to be for the tank below? The path of the spider's thread is shown with a red dotted line. Round your answer to the nearest tenth of an inch The diagonal of the bottom of the tank is inches. To the nearest tenth of an inch, the length of the spider's thread is inches.
1 answer