Given that the sphere, cylinder, and cone all share the same radius and the cylinder and cone also share the same height, we can compare their volumes.
The volume of a sphere with radius $r$ is $\frac{4}{3}\pi r^3$.
The volume of a cylinder with radius $r$ and height $2r$ is $\pi r^2(2r)=2\pi r^3$.
The volume of a cone with radius $r$ and height $2r$ is $\frac{1}{3}\pi r^2(2r)=\frac{2}{3}\pi r^3$.
Comparing the volumes, we see that $\frac{4}{3}\pi r^3 > \frac{2}{3}\pi r^3 > 2\pi r^3$. Since the sphere has the largest volume, it cannot be expressed as the sum of a cylinder and a cone.
Therefore, the answer is $\boxed{\text{(D) } \text{sphere} = \text{cylinder} + \text{cone}}$.
Suppose a sphere, cylinder, and cone all share the same radius and the cylinder and cone also share the same height, which is twice the radius. Which of the following is true about the relationship between the volume formulas for the sphere, cylinder, and cone?
A. 3 cones = 1 cylinder
B. sphere - cone = cylinder
C. 1 cylinder = 2 cones + 1 sphere
D. sphere = cylinder + cone
3 answers
are you sure the answer is D?
You are correct, my previous response is incorrect. I apologize for the mistake. Let's re-examine the problem to find the correct answer.
Given that the radius of the sphere, cylinder, and cone are all the same, let's denote the radius as $r$. The height of the cylinder and cone is twice the radius, so it is given by $2r$.
The volume of a sphere with radius $r$ is $\frac{4}{3}\pi r^3$.
The volume of a cylinder with radius $r$ and height $2r$ is $\pi r^2(2r)=2\pi r^3$.
The volume of a cone with radius $r$ and height $2r$ is $\frac{1}{3}\pi r^2(2r)=\frac{2}{3}\pi r^3$.
Let's compare the volumes and see if any relationships exist.
The volume of the cone is $\frac{2}{3}\pi r^3$, which is less than the volume of the cylinder $2\pi r^3$.
The volume of the sphere $\frac{4}{3}\pi r^3$ is greater than the volume of both the cylinder and cone.
Therefore, we can conclude that $\frac{4}{3}\pi r^3 > 2\pi r^3 > \frac{2}{3}\pi r^3$.
None of the given answer choices reflect this relationship. Thus, none of the choices is true.
Given that the radius of the sphere, cylinder, and cone are all the same, let's denote the radius as $r$. The height of the cylinder and cone is twice the radius, so it is given by $2r$.
The volume of a sphere with radius $r$ is $\frac{4}{3}\pi r^3$.
The volume of a cylinder with radius $r$ and height $2r$ is $\pi r^2(2r)=2\pi r^3$.
The volume of a cone with radius $r$ and height $2r$ is $\frac{1}{3}\pi r^2(2r)=\frac{2}{3}\pi r^3$.
Let's compare the volumes and see if any relationships exist.
The volume of the cone is $\frac{2}{3}\pi r^3$, which is less than the volume of the cylinder $2\pi r^3$.
The volume of the sphere $\frac{4}{3}\pi r^3$ is greater than the volume of both the cylinder and cone.
Therefore, we can conclude that $\frac{4}{3}\pi r^3 > 2\pi r^3 > \frac{2}{3}\pi r^3$.
None of the given answer choices reflect this relationship. Thus, none of the choices is true.
2 answers