Suppose a simple pendulum is used to measure the acceleration due to gravity at various points on the Earth. If g varies by 0.151 % over the various locations where it is sampled, what is the corresponding variation in the period of the pendulum? Assume that the length of the pendulum does not change from one site to another
3 answers
deltaT=sqrt(deltag/g)=sqrt(.00151)
dpnt know
WHEN THE PENDULUM IS ON THE RIGHT ITS RIGHT SO RIGHT IS RIGHT BUT RIGHT IS WRONG
DUE TO YOUR QUESTION U ARE STUPID THANKS HAHAHAHAHA
DUE TO YOUR QUESTION U ARE STUPID THANKS HAHAHAHAHA