suppose a similar rectangular pyramid H28 B24 L22 to the one shown has a scale factor of 2/3. what would be the volume of the new pyramid

1 answer

To find the volume of a pyramid, the formula is:

\[ V = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]

First, we need to calculate the volume of the original pyramid with base dimensions \( B = 24 \) and \( L = 22 \), and a height \( H = 28 \).

  1. Calculate the base area:

\[ \text{Base Area} = B \times L = 24 \times 22 = 528 \]

  1. Calculate the volume of the original pyramid:

\[ V = \frac{1}{3} \times \text{Base Area} \times H = \frac{1}{3} \times 528 \times 28 \]

Calculating this step by step:

\[ 528 \times 28 = 14784 \] \[ V = \frac{1}{3} \times 14784 \approx 4928 \]

Now that we have the volume of the original pyramid, we can calculate the volume of the new pyramid that has a scale factor of \( \frac{2}{3} \).

The volume of similar solids scales with the cube of the scale factor:

\[ \text{Volume of New Pyramid} = V \times \left( \text{Scale Factor}^3 \right) \] \[ \text{Scale Factor}^3 = \left( \frac{2}{3} \right)^3 = \frac{8}{27} \]

Now we can calculate the volume of the new pyramid:

\[ \text{Volume of New Pyramid} = 4928 \times \frac{8}{27} \]

Calculating this step by step:

\[ 4928 \times 8 = 39424 \] \[ \frac{39424}{27} \approx 1457.56 \]

Thus, the volume of the new pyramid is approximately \( \boxed{1457.56} \).