1/2 mv^2 = mgh
or, v^2 = 2gh
Suppose a scrawny 20. kg Wyle was shot straight up with an initial velocity of +50 m/s.
a. Assuming that all his initial Ek was transformed into Eg, what is the maximum height he could reach?
b. Suppose that 20% of his initial Ek were lost due to friction with the air (air resistance).
What is the maximum height he could reach?
2 answers
Would that be 127.6 m and 102.08 m
1 answer