Suppose a rectangle is drawn on a coordinate plane. What is the perimeter of the rectangle if its vertices are at coordinates (0,0),(4,4),(5,3), and (1,−1) Round your answer to the nearest tenth.

1 answer

To find the perimeter of the rectangle with vertices at the coordinates (0,0), (4,4), (5,3), and (1,-1), we first check whether these points actually form a rectangle.

We will calculate the lengths of the sides formed by these points.

  1. Calculate the distances between the points:

    • Distance between (0,0) and (4,4): \[ d = \sqrt{(4-0)^2 + (4-0)^2} = \sqrt{4^2 + 4^2} = \sqrt{16 + 16} = \sqrt{32} = 4\sqrt{2} \]
    • Distance between (4,4) and (5,3): \[ d = \sqrt{(5-4)^2 + (3-4)^2} = \sqrt{1^2 + (-1)^2} = \sqrt{1 + 1} = \sqrt{2} \]
    • Distance between (5,3) and (1,-1): \[ d = \sqrt{(1-5)^2 + (-1-3)^2} = \sqrt{(-4)^2 + (-4)^2} = \sqrt{16 + 16} = \sqrt{32} = 4\sqrt{2} \]
    • Distance between (1,-1) and (0,0): \[ d = \sqrt{(0-1)^2 + (0-(-1))^2} = \sqrt{(-1)^2 + 1^2} = \sqrt{1 + 1} = \sqrt{2} \]
  2. Check if opposite sides are equal: We see that:

    • The distances (0,0) to (4,4) and (5,3) to (1,-1) are both \(4\sqrt{2}\).
    • The distances (4,4) to (5,3) and (1,-1) to (0,0) are both \(\sqrt{2}\).

This shows that opposite sides are equal which is typical of a rectangle. Now we can compute the perimeter.

  1. Calculate the perimeter: The perimeter \(P\) of a rectangle is given by the formula: \[ P = 2(\text{length} + \text{width}) \] Here, we take:

    • Length = \(4\sqrt{2}\)
    • Width = \(\sqrt{2}\)

    Thus: \[ P = 2(4\sqrt{2} + \sqrt{2}) = 2(5\sqrt{2}) = 10\sqrt{2} \]

  2. Calculate \(10\sqrt{2}\) numerically: Using \(\sqrt{2} \approx 1.414\): \[ 10\sqrt{2} \approx 10 \times 1.414 \approx 14.14 \]

Finally, rounding to the nearest tenth, we find:

\[ \text{Perimeter} \approx 14.1 \]

Therefore, the perimeter of the rectangle is approximately \(\boxed{14.1}\).