In this scenario, the man is heterozygous (Tt) for the tongue-curling trait, and the woman is also heterozygous (Tt). Let's consider the possible genotypes and phenotypes of their children.
The possible genotypes of their children can be determined using a Punnett square. Crossing the alleles from the father (Tt) with the alleles from the mother (Tt) results in the following combinations:
| T | t |
----------------
T | TT | Tt |
----------------
t | Tt | tt |
The genotypes that can be produced are TT, Tt, Tt, and tt.
- TT (25% chance): Homozygous dominant genotype resulting in the phenotype of tongue-curling.
- Tt (50% chance): Heterozygous genotype resulting in the phenotype of tongue-curling.
- tt (25% chance): Homozygous recessive genotype resulting in the non-tongue curling phenotype.
Thus, there is a 25% chance of having a child with TT genotype and tongue-curling phenotype, a 50% chance of having a child with a Tt genotype and tongue-curling phenotype, and a 25% chance of having a child with tt genotype and a non-tongue curling phenotype.
Suppose a man who is Tt for tongue-curling marries a woman who is also Tt for this trait. What are the possible genotypes and phenotypes of their children, and the percent chance for each?
1 answer