Suppose a code consist of two letters followed by a digit. Find the number of
(a) Codes
(b) Codes with distinct letters
(c) Codes with the same letters.
2 answers
The number of possible different arrangements would be 26 x 26 x 10 = 6760
the answer of a is 26*26*10*10*10.
the answer of b is 26*25*10*10*10.
of c is 26*1*10*10*10
the answer of b is 26*25*10*10*10.
of c is 26*1*10*10*10
2 answers