To understand the depreciation of the equipment using the straight-line method, we can break down the calculation and analyze the results step-by-step.
-
Initial Cost of Equipment: $17,000
-
Salvage Value: $2,000
-
Depreciable Amount: This is calculated as: \[ \text{Depreciable Amount} = \text{Initial Cost} - \text{Salvage Value} = 17,000 - 2,000 = 15,000 \]
-
Useful Life of Equipment: 5 years
-
Annual Depreciation Expense: This is calculated by dividing the depreciable amount by the useful life: \[ \text{Annual Depreciation} = \frac{\text{Depreciable Amount}}{\text{Useful Life}} = \frac{15,000}{5} = 3,000 \]
Now that we have the annual depreciation, we can summarize how much the equipment will be worth at the end of each year:
-
At the End of Year 0:
- Value = $17,000
-
At the End of Year 1:
- Value = $17,000 - $3,000 = $14,000
-
At the End of Year 2:
- Value = $14,000 - $3,000 = $11,000
-
At the End of Year 3:
- Value = $11,000 - $3,000 = $8,000
-
At the End of Year 4:
- Value = $8,000 - $3,000 = $5,000
-
At the End of Year 5:
- Value = $5,000 - $3,000 = $2,000 (this is the salvage value)
Now we can summarize the points for each year, which aligns with the figures you provided:
- Year 0: $17,000
- Year 1: $14,000
- Year 2: $11,000
- Year 3: $8,000
- Year 4: $5,000
- Year 5: $2,000
To answer related questions:
-
Description of the Plot: The line segment you described on the graph starts at the point (0, 17,000) and moves downward to (5, 2,000), representing the depreciation of the asset over time.
-
Interpretation of Depreciation: The depreciation expense reduces the book value of the asset evenly each year until it reaches its salvage value.
-
Impact of Partial Years: If the business were to sell or reassess the equipment value at any point before the end of year 5, the depreciation for the number of months used beyond the last complete year could be calculated proportionally. For example, if the equipment was used for 6 months into year 6, an additional depreciation expense of $1,500 (half of $3,000) would apply, making the ending value $0.
If you have specific questions related to this situation, please let me know!