a. d = Vo*t + 0.5g*t^2,
d=3*1 + 4.9*1^2 = 7.9m below starting point.
d = 3*2 + 4.9*2^2 = 25.6m
b. Vf^2 = V0^2 + 2g*d,
Vf^2 = 3^2 + 19.6*7.9 = 163.84,
Vf = 12.8m/s.
Vf^2 = 3^2 + 19.6*25.6 = 510.76,
Vf = 22.6m.
suppose a ball thrown downward with initial velocity 3 m/s instead of being dropped
a)what then would be its position after 1s and 2s ?
b)what would its speed be after 1 s and 2 s ?
1 answer
1 answer