suppose a .3 kg mass on a spring that has been compress .1 m has elastic potential energy of 1 j. how much further must the spring be compressed to triple the elastic potential energy?
the answer is .07, but how do i get that?
3 answers
two pellets each with a charge of 1 microcoulomb 10 to the negative 6 c are located 3 cm apart what is the electrical force between them what would be the mass of a object that would experience the same force in the earths gradational field
elastic PE=1/2 k x^2 where x is the total distance. figure k from the first sentence..I assume the .3kg is compressing the spring due to its weight.
1j=mg*distance=1/2 kx^2
k= 2j/.1^1= 200j/m^2
triple energy?
3j=1/2 (200j/m^2)x^2 solve for x.
1j=mg*distance=1/2 kx^2
k= 2j/.1^1= 200j/m^2
triple energy?
3j=1/2 (200j/m^2)x^2 solve for x.
Suppose a 0.30-kg mass on a spring that has been compressed 0.10 m has elastic potential energy of 1.5 J. What is the spring constant?
Select one:
a. 300 N/m
b. 20 N/m
c. 200 N/m
d. 10 N/m
Select one:
a. 300 N/m
b. 20 N/m
c. 200 N/m
d. 10 N/m