Suppose a 115 N force is applied to a lawnmower handle at an angle of 25° with the ground and the lawnmower moves along the surface of the ground. If the lawnmower moves 1,600 m, how much work was done?

Group of answer choices

255,400 J

34,677 J

25,433 J

166,761 J

1 answer

To calculate the work done when a force is applied at an angle, we can use the formula:

\[ \text{Work} = F \cdot d \cdot \cos(\theta) \]

Where:

  • \( F \) is the applied force,
  • \( d \) is the distance moved in the direction of the force,
  • \( \theta \) is the angle between the force and the direction of movement.

Given:

  • \( F = 115 , N \)
  • \( d = 1,600 , m \)
  • \( \theta = 25^\circ \)

First, we need to calculate \( \cos(25^\circ) \):

\[ \cos(25^\circ) \approx 0.9063 \quad (\text{using a calculator}) \]

Now, plug in the values into the work formula:

\[ \text{Work} = 115 , N \times 1,600 , m \times \cos(25^\circ) \] \[ \text{Work} = 115 , N \times 1,600 , m \times 0.9063 \] \[ \text{Work} \approx 115 \times 1,600 \times 0.9063 \] \[ \text{Work} \approx 166,761.12 , J \]

Rounding it to the nearest whole number:

\[ \text{Work} \approx 166,761 , J \]

Thus, the work done is approximately 166,761 J.

The correct answer from the given choices is 166,761 J.