5x^2 + 2x + xy = 2
10x + 2 + y + xy' = 0
Now just plug in your numbers and solve for y'.
Suppose 5x^2+2x+xy=2 and y(2)=−11. Find y′(2) by implicit differentiation.
2 answers
What numbers am i plugging in?
Solving for y' gives me (-y-10x-2)/x.
Plugging in 2 for x doesn't give me the right answer, so I don't know where to go from there.
Solving for y' gives me (-y-10x-2)/x.
Plugging in 2 for x doesn't give me the right answer, so I don't know where to go from there.
1 answer