Suppose $4000 is invested at 6% interest compounded annually. Our formula is f(x)=4000(1.06)x

Question

, where x is the number of years since the investment. How much money will there be in the bank at the end of 5 years? Find f(5)

(1 point)
f(5)=
$
round to the nearest cent

Answer 1

To find the amount of money in the bank at the end of 5 years using the formula \( f(x) = 4000(1.06)^x \), we need to evaluate \( f(5) \).

Substituting \( x = 5 \) into the formula:

\[ f(5) = 4000(1.06)^5 \]

Now, let's calculate \( (1.06)^5 \).

\[ (1.06)^5 \approx 1.338225 \]

Now, multiply this by 4000:

\[ f(5) = 4000 \times 1.338225 \approx 5353.00 \]

Thus, rounding to the nearest cent, we find:

\[ f(5) \approx 5353.00 \]

Therefore, the amount of money in the bank at the end of 5 years is:

\[ \boxed{5353.00} \]